Time And Work Ques 31
Question-
A can finish a piece of work in 24 days. $B$ is $20 \%$ more efficient than A. C is $25 \%$ more efficient than B. In how many days B and C together can finish the same piece of work?
(1) $8 \frac{8}{9}$
(2) $9 \frac{1}{3}$
(3) $8 \frac{5}{8}$
(4) $10 \frac{2}{9}$
(5) $9 \frac{1}{6}$
(IBPS Specialist Officer CWE (Prelim Exam) 31.01.2019)
Show Answer
Correct Answer: (1)
Solution: (1)
Time taken by $A=24$ days
B is $20 \%$ more efficient than A.
$\therefore$ Time taken by $B$ $=\frac{24 \times 100}{120}=20$ days
$C$ is $25 \%$ more efficient than B.
$\therefore$ Time taken by $C$ $=\frac{20 \times 100}{125}=16$ days
$\therefore(B+C)$ ’s 1 day’s work $=\frac{1}{20}+\frac{1}{16}$ $=\frac{4+5}{80}=\frac{9}{80}$
$\therefore$ Required time $=\frac{80}{9}=8 \frac{8}{9}$ days
BETA
