Ratio And Proportion Ques 35
Question-
Sum of present ages of $A$ and $B$ is 87 years. Age of A 2 years hence will be equal to the age of $C$ one year ago and age of $A$ four years hence will be equal to the age of $B$ one year ago. If the ratio of present ages of A and D is $3: 4$, find the difference between present ages of $C$ and $D$.
(1) $\frac{44}{3}$ years
(2) $\frac{41}{3}$ years
(3) $\frac{25}{3}$ years
(4) 52 years
(5) $8 \frac{3}{4}$ years
(IBPS RRBs Officer CWE (Main Exam) 05.11.2017)
Show Answer
Correct Answer: (2)
Solution: (2)
According to the question,
$A+B=87$
$C-1=A+2$
$\Rightarrow C=A+3$
and $A+4=B-1$
$\Rightarrow B=A+5$
From equations (i) and (ii)
$A+A+5=87$
$\Rightarrow 2 A=87-5=82$
$\Rightarrow A=41$ years
$\therefore B=41+5=46$ years
$C=41+3=44$ years
$\therefore \frac{A}{D}=\frac{3}{4}$
$\Rightarrow D=\frac{4}{3} \times 41$ $=\frac{164}{3}$ years
$\therefore$ Required difference $=\frac{164}{3}-41$ $=\frac{164-123}{3}$ $=\frac{41}{3}$ years
BETA
