Probability Ques 9
Question-
There are 9 red, 7 white and 4 black balls in a bag. A bag contains 7 blue balls and 5 yellow balls. If two balls are selected at random, what is the probability that none is yellow?
(1) $\frac{5}{33}$
(2) $\frac{5}{22}$
(3) $\frac{7}{22}$
(4) $\frac{7}{33}$
(5) $\frac{7}{66}$
Show Answer
Correct Answer: (1)
Solution: (1)
Total possible outcomes $={ }^{52} C_{1}=52$
Favourable outcomes $=2={ }^{2} C_{2}$
$\therefore$ Required probability $=\frac{2}{52}=\frac{1}{26}$
BETA
