Probability Ques 49
Question-
Directions : The following paragraph shows the details of male and female students in five different groups. Consider the following paragraph and answer the questions given below :
There are 5 different groups $A$, $B$, $P$, $Q$ and $R$.
There are 9 males and 5 females in group $A$.
There are 5 males and 7 females in group B.
There are 7 males and 4 females in group $P$.
There are 4 males and 6 females in group $Q$.
There are 6 males and 3 females in group $R$.
Two students are selected from group $-Q$ at random one by one with replacement. What is the probability that both the students are females?
(1) $\frac{9}{25}$
(2) $\frac{16}{49}$
(3) $\frac{11}{30}$
(4) $\frac{25}{42}$
(5) $\frac{14}{34}$
Show Answer
Correct Answer: (1)
Solution: (1)
Total possible outcomes $=10$,
Favourable outcomes $=6$
Required probability $=\frac{{ }^{6} C_{1}}{{ }^{10} C_{1}} \times \frac{{ }^{6} C_{1}}{{ }^{10} C_{1}}=\frac{6}{10} \times \frac{6}{10}$ $=\frac{36}{100}$