Number System Ques 40

Question

The sum of nine consecutive odd numbers of set-A is 621 . What is the sum of different set-B of six consecutive even numbers whose lowest number is 15 more than the lowest number of set-A?

498

468

478

488

(5) None of these

(Indian Overseas Bank PO Exam. 22.05.2011)

Show Answer

Answer: (5)

Solution: (5)

Let the nine consecutive odd numbers: $x,x+2,x+4,x+6,x+8,x+10,x+12,x+14,x+16$

ATQ,

$x,x+2,x+4,x+6,x+8,x+10,x+12,x+14,x+16 = 621$

$9x+72 = 621$

$9x =621-72$

$9x=549$

$x=61$

$\therefore $ Smallest number of set-A $=61$

$\therefore $ Smallest number of set-B $=61+15=76$

$\therefore$ 6 consecutive even numbers are:- $76,78,80,82,84,86$

$\therefore$ Required sum $=76+78+80+82+84+86=486$