Number System Ques 40
Question
The sum of nine consecutive odd numbers of set-A is 621 . What is the sum of different set-B of six consecutive even numbers whose lowest number is 15 more than the lowest number of set-A?
498
468
478
488
(5) None of these
(Indian Overseas Bank PO Exam. 22.05.2011)
Show Answer
Answer: (5)
Solution: (5)
Let the nine consecutive odd numbers: $x,x+2,x+4,x+6,x+8,x+10,x+12,x+14,x+16$
ATQ,
$x,x+2,x+4,x+6,x+8,x+10,x+12,x+14,x+16 = 621$
$9x+72 = 621$
$9x =621-72$
$9x=549$
$x=61$
$\therefore $ Smallest number of set-A $=61$
$\therefore $ Smallest number of set-B $=61+15=76$
$\therefore$ 6 consecutive even numbers are:- $76,78,80,82,84,86$
$\therefore$ Required sum $=76+78+80+82+84+86=486$