Miscellaneous Question 68
In each question, there are two different statements given as Quantity I and Quantity II. You have to consider the statements individually and mark your answer accordingly as per the given condition.
(1) Quantity I > Quantity II
(2) Quantity I $<$ Quantity II
(3) Quantity I $\geq$ Quantity II
(4) Quantity I $\leq$ Quantity II
(5) Quantity I = Quantity II or relationship cannot be determined
(Canara Bank PO Exam, 23.12.2018)
- Quantity I : Cost price of article. If an article is sold at $8 \%$ profit instead of $8 \%$ loss, it would have brought Rs. 12 more.
Quantity II : Cost price of the book. A man sells a book at a profit of $20 \%$. If he had bought it at $20 \%$ less and sold it for Rs. 18 less he would have gained $25 \%$.
Show Answer
Correct Answer: 68. (2)
Solution: 68. (2) Quantity - I :
C.P. of article $=$ Rs. $x$. $\therefore(8+8) %$ of $x=12$
$\Rightarrow x \times \frac{16}{100}=12$
$\Rightarrow x=\frac{12 \times 100}{16}=$ Rs. 75
Quantity - II :
C.P. of book $=$ Rs. $x$ (let)
Its S.P. $=\frac{120 x}{100}=$ Rs. $\frac{12 x}{10}$
Case II,
C.P. of book $=$ Rs. $\frac{100 x}{80}$
$=$ Rs. $\frac{8 x}{10}$
Its S.P. $=$ Rs. $\left(\frac{12 x}{10}-18\right)$
$\therefore \frac{12 x}{10}-18=\frac{8 x}{10} \times \frac{125}{100}=\frac{125 x}{100}$
$\Rightarrow \frac{12 x}{10}-x=18$
$\Rightarrow \frac{2 x}{10}=18 \Rightarrow x=\frac{18 \times 10}{2}$
$=$ Rs. 90
Clearly, quantity I $<$ quantity II
BETA
