Miscellaneous Question 46
- Quantity I : Length of the longest rod that can be put inside a square base box of side $8 $ $cm$ and height $24 $ $cm$.
Quantity II : Lenght of the longest rod that can be put inside a cylindrical box of diameter $10 $ $cm$. and height $24 $ $cm$.
(1) Quantity I $>$ Quantity II
(2) Quantity I $<$ Quantity II
(3) Quantity I $\leq$ Quantity II
(4) Quantity I $\geq$ Quantity II
(5) Quantity I = Quantity II or No relation.
(IBPS Bank PO/MT CWE (Main Exam) 26.11.2017)
Show Answer
Correct Answer: 46. (1)
Solution: 46. I. $ \mathrm{L}_{1}=\sqrt{8^{2}+8^{2}+24^{2}}$
$=\sqrt{2 \times 8^{2}+24^{2}}$
$=\sqrt{(8 \sqrt{2})^{2}+24^{2}}$
II. $\mathrm{L}_{2}=\sqrt{10^{2}+24^{2}}$
Since, $(8 \sqrt{2})>10$,
$\mathrm{L} _{1}>\mathrm{L} _{2}$
$\therefore$ Quantity I $>$ Quantity II.
BETA
