Miscellaneous Question 10
- A certain sum is divided among $A, B$ and $C$ in such a way that $A$ gets Rs. 40 more than the $\frac{1}{2}$ of the sum. B gets Rs. 120 less than $\frac{3}{8}$ th of the sum and $C$ gets Rs. 200. What is the total sum?
(1) Rs. 1100
(2) Rs. 850
(3) Rs. 960
(4) Rs. 1200
(5) Rs. 1000
(IBPS Bank PO/MT CWE-V (Preliminary) 03.10.2015)
Show Answer
Correct Answer: 10. (3)
Solution: 10. (3) Let initial amount be Rs. $x$.
$\therefore \mathrm{A} \Rightarrow \frac{x}{2}+40$
$\mathrm{B} \Rightarrow \frac{3 x}{8}-120$
$\therefore$ C’s share
$=x-\frac{x}{2}-40-\frac{3 x}{8}+120$
$=x-\frac{x}{2}-\frac{3 x}{8}+80$
$=\frac{8 x-4 x-3 x}{8}+80$
$=\frac{x}{8}+80$
According to the question,
$\frac{x}{8}+80=200$
$\Rightarrow \frac{x}{8}=200-80=120$
$\Rightarrow x=120 \times 8=$ Rs. 960
BETA
