Mensuration Ques 11
Question
In the following figure, $\triangle ABC$ is an equilateral triangle and BCED is a square whose each side is 8 $cm$ long. Find the area of pentagon $ABDEC$ in square $cm$.
(1) $18(4+\sqrt{3})$
(2) $16(4+\sqrt{3})$
(3) $8(4+\sqrt{3})$
(4) $16(2+\sqrt{3})$
(5) None of these
(IBPS Bank PO/MT CWE-IV 18.10.2014)
Show Answer
Correct Answer: (2)
Solution: (2)
Area of $\triangle ABC=\frac{\sqrt{3}}{4} \times \operatorname{side}^{2}$
$=\frac{\sqrt{3}}{4} \times 8 \times 8=16 \sqrt{3}$ sq. cm.
Area of square BDEC $=8 \times 8$ $=64 sq$. $cm$.
$\therefore$ Area of pentagon ABDEC $=(64+16 \sqrt{3})$ sq. cm.
$=16(4+\sqrt{3})$ sq. cm.
BETA
