Equations And Inequations Ques 99
I. $x^{2}=4$
II. $3 y^{2}+13 y+14=0$
Directions : In the following questions, two equations numbered I and II are given. You have to solve both the equations and give answer If
(1) $x<y$
(2) $x>y$
(3) $x \leq y$
(4) $x \geq y$
(5) $\quad x=y$ or the relationship cannot be established
Show Answer
Correct Answer: 99.(4)
Solution: (4) I. $x^{2}=4$
$\Rightarrow x=\sqrt{4}= \pm 2$
II. $3 y^{2}+13 y+14=0$
$\Rightarrow 3 y^{2}+6 y+7 y+14=0$
$\Rightarrow 3 y(y+2)+7(y+2)=0$
$\Rightarrow(y+2)(3 y+7)=0$
$\Rightarrow y=-2$ or, $\frac{-7}{3}$
Clearly, $x \geq y$
BETA
