Equations And Inequations Ques 90
I. $2 x^{2}+19 x+42=0$
II. $y^{2}+9 y+20=0$
Directions : In the following questions, two equations numbered I and II are given. You have to solve both the equations and give answe If
(1) $x<y$
(2) $x>y$
(3) $x \leq y$
(4) $x \geq y$
(5) $x=y$ or the relationship cannot be established
Show Answer
Correct Answer: 90.(5)
Solution: (5) I. $2 x^{2}+19 x+42=0$
$\Rightarrow 2 x^{2}+12 x+7 x+42=0$
$\Rightarrow 2 x(x+6)+7(x+6)=0$
$\Rightarrow(x+6)(2 x+7)=0$
$\Rightarrow x=-6$ or, $-\frac{7}{2}$
II. $y^{2}+9 y+20=0$
$\Rightarrow y^{2}+4 y+5 y+20=0$
$\Rightarrow y(y+4)+5(y+4)=0$
$\Rightarrow(y+4)(y+5)=0$
$\Rightarrow y=-4$ or, -5
BETA
