Equations And Inequations Ques 79
I. $2 x^{2}+9 x+7=0$
II. $y^{2}+y+4=0$
Directions : In the following questions two equations numbered I and II are given. You have to solve both the equations and give answer
(1) if $x>y$
(2) if $x \geq y$
(3) if $x<y$
(4) if $x \leq y$
(5) if $x=y$ or the relationship between $x$ and $y$ cannot be established.
Show Answer
Correct Answer: 79.(5)
Solution: (5) I. $2 x^{2}+9 x+7=0$
$\Rightarrow 2 x^{2}+2 x+7 x+7=0$
$\Rightarrow 2 x(x+1)+7(x+1)=0$
$\Rightarrow(x+1)(2 x+7)=0$
$\Rightarrow x=-1$ or, $-\frac{7}{2}$
II. $y^{2}+y+4=0$
$y=\frac{-1 \pm \sqrt{1-4 \times 4}}{2}$
$=\frac{-1 \pm \sqrt{-15}}{2}$
BETA
