Equations And Inequations Ques 61
I. $x^{2}+6 x+9=0$
II. $y^{2}-y-20=0$
Directions : In the following questions two equations numbered I and II are given. You have to solve both the equations and give answer
(1) if $x>y$
(2) if $x \geq y$
(3) if $x<y$
(4) if $x \leq y$
(5) if $x=y$ or the relationship between $x$ and $y$ cannot be established.
Show Answer
Correct Answer: 61.(5)
Solution: (5) I. $x^{2}+6 x+9=0$
$\Rightarrow(x+3)^{2}=0$
$\Rightarrow x=-3$
II. $y^{2}-y-20=0$
$\Rightarrow y^{2}-5 y+4 y-20=0$
$\Rightarrow y(y-5)+4(y-5)=0$
$\Rightarrow(y+4)(y-5)=0$
$\Rightarrow y=-4$ or, 5
BETA
