Equations And Inequations Ques 5
I. $3 x^{2}-13 x+12=0$
II. $3 y^{2}-13 y+14=0$
(1) $x \leq y$
(2) $x \geq y$
(3) relationship between $x$ and $y$ cannot be determined
(4) $x<y$
(5) $x>y$
Show Answer
Correct Answer: 5.(3)
Solution: (3) I. $3 x^{2}-13 x+12=0$
$\Rightarrow 3 x^{2}-4 x-9 x+12=0$
$\Rightarrow x(3 x-4)-3(3 x-4)=0$
$\Rightarrow(3 x-4)(x-3)=0$
$\Rightarrow x=\frac{4}{3}$ or 3
II. $3 y^{2}-13 y+14=0$
$\Rightarrow 3 y^{2}-6 y-7 y+14=0$
$\Rightarrow 3 y(y-2)-7(y-2)=0$
$\Rightarrow(3 y-7)(y-2)=0$
$\Rightarrow y=\frac{7}{3}$ or 2
BETA
