Equations And Inequations Ques 33
I. $x^{2}+10 x+24=0$
II. $y^{2}-\sqrt{625}=0$
Directions : In these questions two equations numbered I and II are given. You have to solve both the equations and give answer
(1) if $x<y$
(2) if $x>y$
(3) if $x<y$
(4) if $\quad x \geq y$
(5) if $x=y$ or relationship between $x$ and $y$ cannot be established
(IBPS Bank PO/MT CWE (Pre.), 16.10.2016 (First Sitting)
Show Answer
Correct Answer: 33.(5)
Solution: (5) I. $x^{2}+10 x+24=0$ $\Rightarrow x^{2}+4 x+6 x+24=0$
$\Rightarrow x(x+4)+6(x+4)=0$
$\Rightarrow(x+6)(x+4)=0$
$\Rightarrow x=-6$ or -4
II. $y^{2}-\sqrt{625}=0$
$\Rightarrow y^{2}=\sqrt{625}=25$
$\Rightarrow y= \pm 5$
BETA
