Equations And Inequations Ques 29
I. $x^{2}+6 x+8=0$
II. $2 y^{2}+5 y+3=0$
Directions : In the following questions, two equations numbered I and II are given. You have to solve both the equations and give answer If
(1) $x<y$
(2) $x>y$
(3) $x \leq y$
(4) $x \geq y$
(5) $\quad x=y$ or the relationship cannot be established
(United Bank of India PGDBF Manipal Exam,07.08.2016)
Show Answer
Correct Answer: 29.(1)
Solution: (1) I. $x^{2}+6 x+8=0$
$\Rightarrow x^{2}+4 x+2 x+8=0$
$\Rightarrow x(x+4)+2(x+4)=0$
$\Rightarrow(x+2)(x+4)=0$
$\Rightarrow x=-2$ or, -4
II. $2 y^{2}+5 y+3=0$
$\Rightarrow 2 y^{2}+2 y+3 y+3=0$
$\Rightarrow 2 y(y+1)+3(y+1)=0$
$\Rightarrow(2 y+3)(y+1)=0$
$\Rightarrow y=\frac{-3}{2}$ or -1
Clearly, $x<y$
BETA
