Equations And Inequations Ques 178
I. $x^{2}+3 x-28=0$
II. $y^{2}-y-20=0$
Directions : In the following questions, two equations I and II have been given. You have to solve both equations and give answer if
(1) $x>y$
(2) $x \geq y$
(3) $x<y$
(4) $x \leq y$
(5) $x=y$ or the relation cannot be established.
(IBPS RRBs Officer Scale-I CWE, 06.09.2014)
Show Answer
Correct Answer: 178.(5)
Solution: (5) I. $x^{2}+3 x-28=0$
$\Rightarrow x^{2}+7 x-4 x-28=0$
$\Rightarrow x(x+7)-4(x+7)=0$
$\Rightarrow(x-4)(x+7)=0$
$\Rightarrow x=4$ or -7
II. $y^{2}-y-20=0$
$\Rightarrow y^{2}-5 y+4 y-20=0$
$\Rightarrow y(y-5)+4(y-5)=0$
$\Rightarrow(y+4)(y-5)=0$
$\Rightarrow y=-4$ or 5
BETA
