Equations And Inequations Ques 149
I. $x^{2}-24 x+144=0$
II. $y^{2}-26 y+169=0$
Directions : In each of the following questions, two equations are given. You have to solve these equations and give answer If
(1) $x<y$
(2) $x>y$
(3) $x=y$
(4) $x \geq y$
(5) $x \leq y$
(IBPS Bank PO/MT CWE-III 26.10 .2013 )
Show Answer
Correct Answer: (1)
Solution: (1) I. $x^{2}-24 x+144=0$
$\Rightarrow x^{2}-12 x-12 x+144=0$
$\Rightarrow x(x-12)-12(x-12)=0$
$\Rightarrow(x-12)(x-12)=0$
$\Rightarrow x=12$
II. $y^{2}-26 y+169=0$
$\Rightarrow(y-13)^{2}=0$
$\Rightarrow y-13=0$
$\Rightarrow y=13$
Clearly, $x<y$