Equations And Inequations Ques 142
I. $\frac{15}{\sqrt{X}}-\frac{9}{\sqrt{X}}=(X)^{\frac{1}{2}}$
II. $y^{10}-(36)^{5}=0$
Directions : In the following questions two equations numbered I and II are given. You have to solve both the equations and give answer If
(1) $\quad x>y$
(2) $\quad x \geq y$
(3) $x<y$
(4) $\quad x \leq y$
(5) $\quad x=y$ or the relationship cannot be established
(IDBI Bank Officer Exam.16.09.2012)
Show Answer
Correct Answer: (5)
Solution: (5) I. $\frac{15}{\sqrt{x}}-\frac{9}{\sqrt{x}}=\sqrt{x}$
$\Rightarrow \frac{6}{\sqrt{x}}=\sqrt{x} \Rightarrow x=6$
II. $y^{10}=(36)^{5}=\left(6^{2}\right)^{5}=6^{10}$
$\Rightarrow y=6$
BETA
