Equations And Inequations Ques 141
I. $17 x^{2}+48 x=9$
II. $13 y^{2}=32 y-12$
Directions : In each of these questions, two equations are given. You have to solve these equations and find out the values of $x$ and $y$ and Give answer If
(1) $x<y$
(2) $x>y$
(3) $x \leq y$
(4) $x \geq y$
(5) $x=y$
(Punjab & Sind Bank PO Exam. 23.01.2011)
Show Answer
Correct Answer: (1)
Solution: (1) I. $17 x^{2}+48 x-9=0$
$\Rightarrow 17 x^{2}+51 x-3 x-9=0$ $\Rightarrow 17 x(x+3)-3(x+3)=0$
$\Rightarrow(x+3)(17 x-3)=0$
$\therefore x=-3$ or $\frac{3}{17}$
II. $13 y^{2}-32 y+12=0$
$\Rightarrow 13 y^{2}-26 y-6 y+12=0$
$\Rightarrow 13 y(y-2)-6(y-2)=0$
$\Rightarrow(y-2)(13 y-6)=0$
$\therefore y=2$ or $\frac{6}{13}$
Clearly, $x<y$
BETA
