Equations And Inequations Ques 126
I. $\frac{9}{\sqrt{x}}+\frac{19}{\sqrt{x}}=\sqrt{x}^3$
II. $y^{5}-\frac{(2 \times 14)^{11 / 2}}{\sqrt{y}}=0$
Directions : In the following questions, two equations numbered I and II are given. You have to solve both the equations and give answer If
(1) $x>y$
(2) $x \geq y$
(3) $x<y$
(4) $x \leq y$
(5) $\quad x=y$ or the relationship cannot be established
(Indian Overseas Bank PO Exam. 22.05.2011)
Show Answer
Correct Answer: 5
Solution: (5) I. $9+19=\sqrt{x} \times \sqrt{x}$
$\Rightarrow x=28$
II. $y^{5} \times y^{\frac{1}{2}}=y^{\frac{11}{2}}$
$\Rightarrow y^{\frac{11}{2}}=(28)^{\frac{11}{2}}$
$\Rightarrow y=28$
BETA
