Quantitative Aptitude Ques 782
Question: Directions: In the following questions, two equations numbered I and II are given. You have to solve both the equations and give answer.
I. $ {{(17)}^{2}}+114\div 18=x $
II. $ {{(26)}^{2}}-18\times 21=y $
Options:
A) If $ x>y $
B) If $ x\ge y $
C) If $ x<y $
D) If $ x\le y $
E) If $ x=y $ or the relationship cannot be established
Show Answer
Answer:
Correct Answer: C
Solution:
- I. $ {{(17)}^{2}}+114\cdot 18=x $
$ \Rightarrow $ $ 17^{2}+\frac{114}{18}=x $
$ \Rightarrow $ $ 289+6.33=x $
$ \Rightarrow $ $ 295.33=x $ II. $ {{(26)}^{2}}-18\times 21=y $
$ \Rightarrow $ $ 676-378=y $
$ \Rightarrow $ $ 298=y $
$ \therefore $ $ y>x $
BETA
