Quantitative Aptitude Ques 481
Question: If $ {{(0.64)}^{4}}\div {{(0.512)}^{3}}\times {{(0.8)}^{4}}={{(0.8)}^{x+3}}, $ then the value of x is [IOB (PO) 2011]
Options:
A) 5
B) 12
C) 0
D) 6
E) None of these
Show Answer
Answer:
Correct Answer: C
Solution:
- $ \frac{{{(0.64)}^{4}}}{{{(0.512)}^{3}}}\times {{(0.8)}^{4}}={{(0.8)}^{x+3}} $
$ \Rightarrow $ $ \frac{{{(0.8)}^{8}}}{{{(0.8)}^{9}}}\times {{(0.8)}^{4}}={{(0.8)}^{x+3}} $
$ \Rightarrow $ $ {{(0.8)}^{3}}={{(0.8)}^{x+3}} $
$ \Rightarrow $ $ x+3=3 $
$ \therefore $ $ x=0 $
BETA
