Quantitative Aptitude Ques 2223
Question: A watch which gain uniformly, is 5 min slow at 7 O’clock in the morning on Sunday and it is 5 min 48 s fast at 7 pm on following Sunday. Which day was it correct?
Options:
A) Friday
B) Saturday
C) Tuesday
D) Wednesday
Show Answer
Answer:
Correct Answer: D
Solution:
- Time from 7 am on Sunday to 7 pm on following Sunday = 7 days 12 h = 180h
$ \therefore $ Watch gains $ ( 5+5\frac{4}{5} )\min $ or $ \frac{54}{5}\min $ in $ 180h. $ Now, $ \frac{54}{5}\min $ are gained in $ 180h. $
$ \therefore $ 5 min are gained in $ =( 180\times \frac{5}{54}\times 5 )h $ $ =83h20\min $ = 3 days 11 h and 20 min $ \because $ Watch is correct after 3 days 11 h and 20 min after 7 am of Sunday. It will be correct at 20 min past 6 pm on Wednesday.
BETA
