Quantitative Aptitude Ques 177
Question: $ \frac{\tan A+\tan B}{\cot A+\cot ,B} $ is equal to
Options:
A) $ \cot A,\cot B $
B) $ \sec A,cosec,B $
C) $ \tan A,\tan B $
D) None of these
Show Answer
Answer:
Correct Answer: C
Solution:
- $ \frac{\tan A+\tan B}{\cot A+\cot B}=\frac{\tan A+\tan B}{\frac{1}{\tan A}+\frac{1}{\tan B}} $ $ =\frac{\tan B+\tan B}{\frac{\tan B+\tan A}{\tan A\cdot \tan B}}=\frac{1}{\frac{1}{\tan A\cdot \tan B}} $ $ =\tan A\cdot \tan B $
BETA
