Simplification Ques 44
Question-
$(5568 \div 87)^{1 / 3}+(72 \times 2)^{1 / 2}=(\text { ? })^{1 / 2}$
(1) 256
(2) 4
(3) $\sqrt{2}$
(4) 16
(5) None of these
RBI GRADE-B/ NABARD GRADE-A OFFICER EXAMS
Show Answer
Correct Answer: (1)
Solution: (1)
$\left(\frac{5568}{87}\right)^{\frac{1}{3}}+(72 \times 2)^{\frac{1}{2}}=(?)^{\frac{1}{2}}$
$ \Rightarrow(64)^{\frac{1}{3}}+(144)^{\frac{1}{2}}=(?)^{\frac{1}{2}} $
$ \Rightarrow\left(4^{3}\right)^{\frac{1}{3}}+\left(12^{2}\right)^{\frac{1}{2}}=(?)^{\frac{1}{2}} $
$ \Rightarrow 4+12=(?)^{\frac{1}{2}} $
$\Rightarrow(?)^{\frac{1}{2}}=16 $
$ \Rightarrow ?=16^{2}=16 \times 16=256$
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