Simplification Ques 24
Question-
$(8)^{3} \div(16)^{2} \times 32= (2)^{?-4} \div (4)^{2}$
(1) 12
(2) 18
(3) 14
(4) 10
(5) None of these
Show Answer
Correct Answer: (3)
Solution: (3)
$\left(2^{3}\right)^{3} \div\left(2^{4}\right)^{2} \times 2^{5}=\frac{2^{?-4}}{\left(2^{2}\right)^{2}}$
$\Rightarrow 2^{9} \div 2^{8} \times 2^{5} \times 2^{4}=2^{?-4}$
$\left[a^{m} \times a^{n}=a^{m+n}\right]$
$\Rightarrow \frac{2^{9} \times 2^{5} \times 2^{4}}{2^{8}}=2^{?-4}$
$\Rightarrow 2^{9+5+4-8}=2^{?-4}$
$\Rightarrow 2^{10}=2^{?-4}$
$\left[a^{m} \div a^{n}=a^{m-n}\right]$
$\Rightarrow ?-4=10 $
$\Rightarrow ?=10+4=14$
BETA
