Probability Ques 17
Question-
Three unbiased coins were tossed in the air simultaneously. What is the probability of getting more than one head?
(1) $\frac{1}{4}$
(2) $\frac{1}{2}$
(3) $\frac{3}{4}$
(4) $\frac{3}{8}$
(5) Other than those given as options
(Bank of Maharashtra PO Exam, 26.10.2016)
Show Answer
Correct Answer: (2)
Solution: (2)
Total possible outcomes $=2 \times 2 \times 2=8$
Total favourable outcomes $=(HHT),(HTH),(HHH),(THH)$
$\therefore$ Required probability $=\frac{4}{8}=\frac{1}{2}$
BETA
