Probability Ques 11
Question-
There are 9 red, 7 white and 4 black balls in an bag.
If two balls are selected at random what is the probability that one ball is white and the other ball is red?
(1) $\frac{91}{190}$
(2) $\frac{63}{190}$
(3) $\frac{5}{19}$
(4) $\frac{4}{95}$
(5) $\frac{71}{190}$
Show Answer
Correct Answer: (2)
Solution: (2)
Total possible outcomes $=190$
Favourable outcomes $=$ Selection of 1 ball out of 9 red balls and 1 ball from 7 white balls $={ }^{9} C_{1} \times{ }^{7} C_{1}=9 \times 7=63$
$\therefore$ Required probability $=\frac{63}{190}$
BETA
