Number System Ques 7
Question
Farah was married 8 years ago.Today her age is $1 \frac{2}{7}$ times to that at the time of marriage. At present her daughter’s age is $\frac{1}{6}$ th of her age. What was her daughter’s age 3 years ago?
(1) 6 years
(2) 7 years
(3) 3 years
(4) Cannot be determined
(5) None of these
(IBPS Specialist Officer CWE 17.03.2013)
Show Answer
Answer: (3)
Solution: (3)
$1 \frac{2}{7}=\underset{7}{9} \rightarrow$ Present age of Farah marriage of Farah
Difference $=9-7=2$
$\because 2$ unit $=8$ years
$\therefore 1$ unit $=4$ years
$\therefore$ Present age of Farah $=9$ unit $=9 \times 4=36$ years
Now, present age of her daughter $=\frac{1}{6} \times 36=6$ years
$\therefore$ Daughter’s age 3 years ago $=6-3=3$ years .
BETA
