Miscellaneous Question 94
In each question, there are two different statements given as Quantity I and Quantity II. You have to consider the statements individually and mark your answer accordingly as per the given codes.
(1) Quantity I $>$ Quantity II
(2) Quantity I $<$ Quantity II
(3) Quantity I $\geq$ Quantity II
(4) Quantity I $\leq$ Quantity II
(5) Quantity I = Quantity II or relationship cannot be established
(IBPS RRBs Officer CWE Prelim Exam, 13.09.2020)
- Quantity I : A and B can do a work in $\frac{8}{3}$ days, $B$ and $C$ can do the same work in 3 days and $A$ and $C$ can do the same work in 24 $\frac{24}{5}$ days. In what time $C$ alone can complete the work?
Quantity II : 15
Show Answer
Correct Answer: 94. (2)
Solution: 94. (2) (A+B)’s 1 day’s work
$=\frac{3}{8} \ldots$. (i)
(B + C)’s 1 day’s work
$=\frac{1}{3}$
(C + A)’s 1 day’s work
$=\frac{5}{24}$
On adding all three,
2 (A+B + C)’s 1 day’s work
$=\frac{3}{8}+\frac{1}{3}+\frac{5}{24}$
$=\frac{9+8+5}{24}=\frac{22}{24}=\frac{11}{12}$
$\therefore(\mathrm{A}+\mathrm{B}+\mathrm{C})$ ’s 1 day’s work
$=\frac{11}{24} \ldots$. (iv)
$\therefore$ C’s 1 day’s work = Equation (iv) - (i).
$=\frac{11}{24}-\frac{3}{8}$
$=\frac{11-9}{24}=\frac{2}{24}=\frac{1}{12}$
$\therefore$ Required time
$=12$ days
Clearly, quantity I < quantity II
BETA
