Equations And Inequations Ques 78
I. $x^{2}-8 x+15=0$
II. $y^{2}-12 y+36=0$
Directions : In the following questions two equations numbered I and II are given. You have to solve both the equations and give answer
(1) if $x>y$
(2) if $x \geq y$
(3) if $x<y$
(4) if $x \leq y$
(5) if $x=y$ or the relationship between $x$ and $y$ cannot be established.
Show Answer
Correct Answer: 78.(3)
Solution: (3) I. $x^{2}-8 x+15=0$
$\Rightarrow x^{2}-3 x-5 x+15=0$
$\Rightarrow x(x-3)-5(x-3)=0$
$\Rightarrow(x-5)(x-3)=0$
$\Rightarrow x=5$ or, 3
II. $y^{2}-12 y+36=0$
$\Rightarrow(y-6)^{2}=0$
$\Rightarrow y=6$
Clearly, $x<y$
BETA
