Equations And Inequations Ques 69
I. $4 x^{2}+12 x+5=0$
II. $y^{2}+7 y+12=0$
Directions : In each of the following questions, two equations numbered I and II are given. You have to solve both the equations and give answer
(1) if $x \geq y$
(2) if $x \leq y$
(3) if $x>y$
(4) if $x<y$
(5) if relationship between $x$ and $y$ cannot be established
(IBPS SO (Agriculture) Exam, 29.01.2017)
Show Answer
Correct Answer: 69.(3)
Solution: (3) I. $4 x^{2}+12 x+5=0$ $\Rightarrow 4 x^{2}+2 x+10 x+5=0$
$\Rightarrow 2 x(2 x+1)+5(2 x+1)=0$
$\Rightarrow(2 x+1)(2 x+5)=0$
$\Rightarrow x=-\frac{1}{2}$ or, $-\frac{5}{2}$
II. $y^{2}+7 y+12=0$
$\Rightarrow y^{2}+4 y+3 y+12=0$
$\Rightarrow y(y+4)+3(y+4)=0$
$\Rightarrow(y+4)(y+3)=0$
$\Rightarrow y=-4$ or, -3
Clearly, $x>y$
BETA
