Equations And Inequations Ques 6
I. $5 x^{2}+8 x+3=0$
II. $3 y^{2}+7 y+4=0$
(1) $x \leq y$
(2) $x \geq y$
(3) relationship between $x$ and $y$ cannot be determined
(4) $x<y$
(5) $x>y$
Show Answer
Correct Answer: 6.(2)
Solution: (2) I. $5 x^{2}+8 x+3=0$
$\Rightarrow 5 x^{2}+5 x+3 x+3=0$
$\Rightarrow 5 x(x+1)+3(x+1)=0$
$\Rightarrow(5 x+3)(x+1)=0$
$\Rightarrow x=\frac{-3}{5}$ or -1
II. $3 y^{2}+7 y+4=0$
$\Rightarrow 3 y^{2}+3 y+4 y+4=0$
$\Rightarrow 3 y(y+1)+4(y+1)=0$
$\Rightarrow(y+1)(3 y+4)=0$
$\Rightarrow y=-1$ or $\frac{-4}{3}$
BETA
