Equations And Inequations Ques 53
I. $x^{2}=196$
II. $y^{2}+2 y-48=0$
Directions : In the following questions two equations numbered I and II are given. You have to solve both the equations and give answer
(1) if $x>y$
(2) if $x \geq y$
(3) if $x<y$
(4) if $x \leq y$
(5) if $x=y$ or the relationship between $x$ and $y$ cannot be established.
(IBPS RRBs Officer CWE (Pre.) 14.11.2016 (Shift-I))
Show Answer
Correct Answer: 53.(5)
Solution: (5) I. $x^{2}=196$
$$ \begin{aligned} & \Rightarrow x=\sqrt{196}= \pm 14 \\ & \text { II. } y^{2}+2 y-48=0 \\ & \Rightarrow y^{2}+8 y-6 y-48=0 \\ & \Rightarrow y(y+8)-6(y+8)=0 \\ & \Rightarrow(y-6)(y+8)=0 \\ & \Rightarrow y=6 \text { or, }-8 \end{aligned} $$
BETA
