Equations And Inequations Ques 44
I. $16 x^{2}-14 x+3=0$
II. $6 y^{2}-19 y+15=0$
Directions : In the following questions, two equations numbered I and II are given. You have to solve both the equations and give answer. If
(1) $x<y$
(2) $x>y$
(3) $x \leq y$
(4) $x \geq y$
(5) $\quad x=y$ or the relationship cannot be established
(IBPS Bank PO/MT (Pre.) Exam, 23.10.2016)
Show Answer
Correct Answer: 44.(1)
Solution: (1) I. $16 x^{2}-14 x+3=0$
$\Rightarrow 16 x^{2}-8 x-6 x+3=0$
$\Rightarrow 8 x(2 x-1)-3(2 x-1)=0$
$\Rightarrow(8 x-3)(2 x-1)=0$
$\Rightarrow x=\frac{3}{8}$ or $x=\frac{1}{2}$ II. $6 y^{2}-19 y+15=0$
$\Rightarrow 6 y^{2}-10 y-9 y+15=0$
$\Rightarrow 2 y(3 y-5)-3(3 y-5)=0$
$\Rightarrow(2 y-3)(3 y-5)=0$
$\Rightarrow y=\frac{3}{2}$ or, $\frac{5}{3}$
Clearly, $x<y$
BETA
