Equations And Inequations Ques 4
I. $2 x^{2}+15 x+27=0$
II. $2 y^{2}+7 y+6=0$
(1) $ x \leq y $
(2) $x \geq y$
(3) relationship between $x$ and $y$ cannot be determined
(4) $ x<y $
(5) $ x>y$
Show Answer
Correct Answer: 4.(4)
Solution: (4) I. $2 x^{2}+15 x+27=0$
$\Rightarrow 2 x^{2}+6 x+9 x+27=0$
$\Rightarrow 2 x(x+3)+9(x+3)=0$
$\Rightarrow(2 x+9)(x+3)=0$
$\Rightarrow x=\frac{-9}{2}$ or -3
II. $2 y^{2}+7 y+6=0$
$\Rightarrow 2 y^{2}+4 y+3 y+6=0$
$\Rightarrow 2 y(y+2)+3(y+2)=0$
$\Rightarrow(2 y+3)(y+2)=0$
$\Rightarrow y=-\frac{3}{2}$ or -2
Clearly, $x<y$
BETA
