Equations And Inequations Ques 28
I. $4 x^{2}-x-68=0$
II. $3 y^{2}+10 y+8=0$
Directions : In the following questions, two equations numbered I and II are given. You have to solve both the equations and give answer If
(1) $x<y$
(2) $x>y$
(3) $x \leq y$
(4) $x \geq y$
(5) $\quad x=y$ or the relationship cannot be established
(United Bank of India PGDBF Manipal Exam,07.08.2016)
Show Answer
Correct Answer: 28.(5)
Solution: (5) I. $4 x^{2}-x-68=0$
$\Rightarrow 4 x^{2}+16 x-17 x-68=0$
$\Rightarrow 4 x(x+4)-17(x+4)=0$
$\Rightarrow(x+4)(4 x-17)=0$
$\Rightarrow x=-4$ or $\frac{17}{4}$
II. $3 y^{2}+10 y+8=0$
$\Rightarrow 3 y^{2}+6 y+4 y+8=0$
$\Rightarrow 3 y(y+2)+4(y+2)=0$
$\Rightarrow(3 y+4)(y+2)=0$
$\Rightarrow y=-\frac{4}{3}$ or -2
BETA
