Equations And Inequations Ques 25
I. $x^{2}+4 x+4=0$
II. $y^{2}+4 y+3=0$
Directions : In the following questions, two equations numbered I and II are given. You have to solve both the equations and give answer If
(1) $x<y$
(2) $x>y$
(3) $x \leq y$
(4) $x \geq y$
(5) $\quad x=y$ or the relationship cannot be established
(United Bank of India PGDBF Manipal Exam,07.08.2016)
Show Answer
Correct Answer: 25.(5)
Solution: (5) I. $x^{2}+4 x+4=0$
$\Rightarrow(x+2)^{2}=0 \Rightarrow x+2=0$ $\Rightarrow x=-2$,
II. $y^{2}+4 y+3=0$
$\Rightarrow y^{2}+y+3 y+3=0$
$\Rightarrow y(y+1)+3(y+1)=0$
$\Rightarrow(y+1)(y+3)=0$
$\Rightarrow y=-1$ or -3
BETA
