Equations And Inequations Ques 186
I. $x^{2}=16$
II. $2 y^{2}-17 y+36=0$
(1) $x>y$
(2) $x \geq y$
(3) $x<y$
(4) relationship between $x$ and $y$ cannot be determined
(5) $x \leq y$
Show Answer
Correct Answer: 186.(5)
Solution: (5) I. $x^{2}=16$
$\Rightarrow x=\sqrt{16}= 4$
II. $2 y^{2}-17 y+36=0$
$\Rightarrow 2 y^{2}-8 y-9 y+36=0$
$\Rightarrow 2 y(y-4)-9(y-4)=0$
$\Rightarrow(2 y-9)(y-4)=0$
$\Rightarrow y=\frac{9}{2}$ or $4$
Clearly, $x \leq y$
BETA
