Equations And Inequations Ques 185
I. $3 x^{2}-13 x+12=0$
II. $2 y^{2}-15 y+28=0$
(1) $x>y$
(2) $x \geq y$
(3) $x<y$
(4) relationship between $x$ and $y$ cannot be determined
(5) $x \leq y$
Show Answer
Correct Answer: 185.(3)
Solution: (3) I. $3 x^{2}-13 x+12=0$
$\Rightarrow 3 x^{2}-4 x-9 x+12=0$
$\Rightarrow x(3 x-4)-3(3 x-4)=0$
$\Rightarrow(x-3)(3 x-4)=0$
$\Rightarrow x=3$ or, $\frac{4}{3}$
II. $2 y^{2}-15 y+28=0$
$\Rightarrow 2 y^{2}-7 y-8 y+28=0$
$\Rightarrow y(2 y-7)-4(2 y-7)=0$
$\Rightarrow(y-4)(2 y-7)=0$
$\Rightarrow y=4$ or, $\frac{7}{2}$
Clearly, $x<y$
BETA
