Equations And Inequations Ques 181
I. $6 x^{2}+19 x+15=0$
II. $24 y^{2}+11 y+1=0$
Directions : In the following questions two equations numbered I and II are given. You have to solve both the equations and give answer If
(1) $x>$
(2) $\quad x \geq y$
(3) $x<y$
(4) $x \leq y$
(5) $\quad x=y$ or the relationship cannot be established
(IBPS Bank PO/MT CWE-IV 18.10.2014)
Show Answer
Correct Answer: 181.(3)
Solution: (3) I. $6 x^{2}+19 x+15=0$
$\Rightarrow 6 x^{2}+10 x+9 x+15=0$
$\Rightarrow 2 x(3 x+5)+3(3 x+5)=0$
$\Rightarrow(2 x+3)(3 x+5)=0$
$\Rightarrow x=\frac{-3}{2}$ or $\frac{-5}{3}$
II. $24 y^{2}+11 y+1=0$
$\Rightarrow 24 y^{2}+8 y+3 y+1=0$
$\Rightarrow 8 y(3 y+1)+1(3 y+1)=0$
$\Rightarrow(8 y+1)(3 y+1)=0$
$\Rightarrow y=\frac{-1}{8}$ or $\frac{-1}{3}$
Clearly, $x<y$
BETA
