Equations And Inequations Ques 156
I. $12 x^{2}+17 x+6=0$
II. $6 y^{2}+5 y+1=0$
Directions : In each of the following questions equation I and equation II have been given. You have to solve both of these equations and give answer If
(1) $x<y$
(2) $x>y$
(3) $x \leq y$
(4) $x \geq y$
(5) $x=y$ or no relation between two can be established.
(Corporation Bank Specialist Officer (Marketing) Exam. 22.02.2014)
Show Answer
Correct Answer: (1)
Solution: (1) I. $12 x^{2}+17 x+6=0$
$\Rightarrow 12 x^{2}+9 x+8 x+6=0$
$\Rightarrow 3 x(4 x+3)+2(4 x+3)=0$
$\Rightarrow(4 x+3)(3 x+2)=0$
$\Rightarrow x=-\frac{3}{4}$ or $-\frac{2}{3}$
II. $6 y^{2}+5 y+1=0$
$\Rightarrow 6 y^{2}+2 y+3 y+1=0$
$\Rightarrow 2 y(3 y+1)+1(3 y+1)=0$
$\Rightarrow(3 y+1)(2 y+1)=0$
$\Rightarrow y=-\frac{1}{3}$ or $-\frac{1}{2}$
Clearly, $x<y$
BETA
