Equations And Inequations Ques 148
I. $x^{2}+4 x+4=0$
II. $y^{2}-8 y+16=0$
Directions : In each of the following questions two equations are given. Solve these equations and give answer :
(1) if $x \geq y$, i.e., $x$ is greater than or equal to $y$
(2) if $x>y$, i.e., $x$ is greater than $y$
(3) if $x \leq y$, i.e., $x$ is less than or equal to $y$
(4) if $x<y$, i.e., $x$ less than $y$
(5) $x=y$ or no relation can be established between $x$ and $y$
(IBPS Specialist Officer CWE 17.03.2013)
Show Answer
Correct Answer: (4)
Solution: (4) I. $x^{2}+4 x+4=0$
$(x+2)^{2}=0 \Rightarrow x=-2$
II. $y^{2}-8 y+16=0$
$\Rightarrow(y-4)^{2}=0$
$\Rightarrow y=4$
BETA
