Equations And Inequations Ques 138

I. $18 x^{2}+18 x+4=0$

II. $12 y^{2}+29 y+14=0$

Directions : In each of these questions, two equations are given. You have to solve these equations and find out the values of $x$ and $y$ and Give answer If

(1) $x<y$

(2) $x>y$

(3) $x \leq y$

(4) $x \geq y$

(5) $x=y$

(Punjab & Sind Bank PO Exam. 23.01.2011)

Show Answer

Correct Answer: (4)

Solution: (4) I. $18 x^{2}+18 x+4=0$

$\Rightarrow 9 x^{2}+9 x+2=0$

$\Rightarrow 9 x^{2}+6 x+3 x+2=0$

$\Rightarrow 3 x(3 x+2)+1(3 x+2)=0$

$\Rightarrow(3 x+1)(3 x+2)=0$

$\therefore x=-\frac{1}{3}$ or $-\frac{2}{3}$

II. $12 y^{2}+29 y+14=0$

$\Rightarrow 12 y^{2}+21 y+8 y+14=0$

$\Rightarrow 3 y(4 y+7)+2(4 y+7)=0$

$\Rightarrow(3 y+2)(4 y+7)=0$

$\therefore y=-\frac{2}{3}$ or $-\frac{7}{4}$

Clearly, $x \geq y$