Equations And Inequations Ques 138
I. $18 x^{2}+18 x+4=0$
II. $12 y^{2}+29 y+14=0$
Directions : In each of these questions, two equations are given. You have to solve these equations and find out the values of $x$ and $y$ and Give answer If
(1) $x<y$
(2) $x>y$
(3) $x \leq y$
(4) $x \geq y$
(5) $x=y$
(Punjab & Sind Bank PO Exam. 23.01.2011)
Show Answer
Correct Answer: (4)
Solution: (4) I. $18 x^{2}+18 x+4=0$
$\Rightarrow 9 x^{2}+9 x+2=0$
$\Rightarrow 9 x^{2}+6 x+3 x+2=0$
$\Rightarrow 3 x(3 x+2)+1(3 x+2)=0$
$\Rightarrow(3 x+1)(3 x+2)=0$
$\therefore x=-\frac{1}{3}$ or $-\frac{2}{3}$
II. $12 y^{2}+29 y+14=0$
$\Rightarrow 12 y^{2}+21 y+8 y+14=0$
$\Rightarrow 3 y(4 y+7)+2(4 y+7)=0$
$\Rightarrow(3 y+2)(4 y+7)=0$
$\therefore y=-\frac{2}{3}$ or $-\frac{7}{4}$
Clearly, $x \geq y$