Equations And Inequations Ques 103
I. $(625)^{\frac{1}{4}} x+\sqrt{1225}=155$
II. $\sqrt{196} y+13=279$
Directions : In the following questions two equations numbered I and II are given. You have to solve both the equations and give answer If
(1) $x>y$
(2) $x \geq y$
(3) $x<y$
(4) $x \leq y$
(5) $x=y$ or the relationship cannot be estab lished
(Allahabad Bank PO Exam. 17.04.2011)
Show Answer
Correct Answer: (1)
Solution: (1) I. $(625)^{\frac{1}{4}} x+\sqrt{1225}=155$
$\Rightarrow\left(5^{4}\right)^{\frac{1}{4}} x+35=155$
$\Rightarrow 5 x=155-35$
$\Rightarrow 5 x=120$
$\Rightarrow x=\frac{120}{5}=24$
II. $\sqrt{196} y+13=279$
$\Rightarrow 14 y=279-13=266$
$\Rightarrow y=\frac{266}{14}=19$
BETA
