Equations And Inequations Ques 101
I. $\sqrt{25 x^{2}}-125=0$
II. $\sqrt{361} y+95=0$
Directions : In the following questions two equations numbered I and II are given. You have to solve both the equations and give answer If
(1) $x>y$
(2) $x \geq y$
(3) $x<y$
(4) $x \leq y$
(5) $x=y$ or the relationship cannot be estab lished
(Allahabad Bank PO Exam. 17.04.2011)
Show Answer
Correct Answer: (5)
Solution: (5) I.
$\sqrt{25 x^{2}}-125=0$
$\Rightarrow \sqrt{25 x^{2}}=125$
$\Rightarrow 25 x^{2}=125 \times 125$
$\Rightarrow x^{2}=\frac{125 \times 125}{25}=625$
$\therefore x=\sqrt{625}= \pm 25$
II. $\sqrt{361} y+95=0$
$\Rightarrow 19 y=-95 \Rightarrow y=-5$
BETA
