Direction Sense - Theory & Concepts

🧭 Direction Sense - Complete Theory

Master directional navigation - the most calculation-based reasoning topic!


🎯 What is Direction Sense?

Direction Sense questions test your ability to:

  • Track movement in different directions
  • Calculate final position from starting point
  • Find shortest distance using Pythagoras theorem
  • Understand compass directions and turns

Example:

A person walks 5 km North, then 3 km East.
What is the shortest distance from starting point?

Answer: √(5² + 3²) = √34 km

πŸ“ Basic Directions

Cardinal Directions (Main)

              North (N)
                 ↑
                 |
                 |
West (W) ←-------+-------β†’ East (E)
                 |
                 |
                 ↓
              South (S)

Key Points:

  • North ↔ South (Opposite)
  • East ↔ West (Opposite)
  • 4 main directions = Cardinal directions

Ordinal Directions (Diagonal)

        NW      N      NE
          \     |     /
           \    |    /
            \   |   /
        W ----  +  ---- E
            /   |   \
           /    |    \
          /     |     \
        SW      S      SE

8 Total Directions:

  1. North (N)
  2. North-East (NE)
  3. East (E)
  4. South-East (SE)
  5. South (S)
  6. South-West (SW)
  7. West (W)
  8. North-West (NW)

πŸ”„ Turns and Rotations

Right Turn (Clockwise)

Starting from NORTH, turning RIGHT:

N β†’ E β†’ S β†’ W β†’ N (360Β° cycle)

Each right turn = 90Β° clockwise

Examples:

Facing North + Right turn = Facing East
Facing East + Right turn = Facing South
Facing South + Right turn = Facing West
Facing West + Right turn = Facing North

Left Turn (Anti-clockwise)

Starting from NORTH, turning LEFT:

N β†’ W β†’ S β†’ E β†’ N (360Β° cycle)

Each left turn = 90Β° anti-clockwise

Examples:

Facing North + Left turn = Facing West
Facing West + Left turn = Facing South
Facing South + Left turn = Facing East
Facing East + Left turn = Facing North

About Turn (180Β°)

About turn = 2 consecutive right turns OR 2 consecutive left turns

Facing North + About turn = Facing South
Facing East + About turn = Facing West
Facing South + About turn = Facing North
Facing West + About turn = Facing East

πŸ“Š Angle-Based Turns

Standard Angles

Right angle = 90Β°
Straight angle = 180Β° (About turn)
Complete rotation = 360Β°

Calculating Final Direction

From North:
- 90Β° clockwise = East
- 180Β° clockwise = South
- 270Β° clockwise = West
- 360Β° clockwise = North (back to start)

From North:
- 45Β° clockwise = North-East
- 135Β° clockwise = South-East
- 225Β° clockwise = South-West
- 315Β° clockwise = North-West

πŸ’‘ Solved Examples

Example 1: Basic Movement

Q: A man walks 3 km North, then turns right and walks 4 km. How far is he from the starting point?

Solution:

Step 1: Draw diagram

        Final (B)
          |
          | 4 km (East)
          |
Start ----+
(A)   3 km
      (North)

Movement:
A β†’ 3 km North β†’ Point P
P β†’ Turn right (now facing East) β†’ 4 km East β†’ Point B

Step 2: Calculate shortest distance (A to B)

Forms a right triangle:
- One side (North) = 3 km
- Other side (East) = 4 km

Using Pythagoras:
DistanceΒ² = 3Β² + 4Β²
DistanceΒ² = 9 + 16 = 25
Distance = 5 km

Answer: 5 km


Example 2: Multiple Turns

Q: A person starts facing North. He turns 90Β° right, then 180Β° left, then 90Β° right. Which direction is he facing now?

Solution:

Step 1: Track each turn

Start: Facing North (N)

Turn 1: 90Β° right
N β†’ E (Facing East)

Turn 2: 180Β° left
E β†’ 180Β° anti-clockwise
E β†’ N β†’ W (Facing West)

Turn 3: 90Β° right
W β†’ 90Β° clockwise
W β†’ N (Facing North)

Answer: North


Example 3: Distance Calculation

Q: Ram walks 5 km East, then 5 km North, then 5 km West. What is the shortest distance from starting point?

Solution:

Step 1: Draw path

      C ← 5 km W ← B
      |            ↑
      |            | 5 km N
      |            |
      Start β†’ 5 km E β†’ A

Step 2: Simplify

Net East-West displacement:
5 km East - 5 km West = 0 km (canceled out)

Net North-South displacement:
5 km North = 5 km North

Step 3: Final position

Ram is 5 km North of starting point
Shortest distance = 5 km

Answer: 5 km North (or just 5 km)


Example 4: Diagonal Movement

Q: A person walks 10 km North-East. What is his displacement in North and East directions?

Solution:

Step 1: Understand North-East

North-East = 45Β° angle between North and East

        NE (10 km)
       /|
      / |
     /  | North component
    /   |
   /45Β° |
  /_____|
   East
  component

Step 2: Calculate components

For 45Β° angle:
North component = 10 Γ— cos(45Β°) = 10 Γ— (1/√2) = 10/√2 km
East component = 10 Γ— sin(45Β°) = 10 Γ— (1/√2) = 10/√2 km

Both are equal = 10/√2 = 5√2 β‰ˆ 7.07 km

Answer: 7.07 km North and 7.07 km East


Example 5: Complex Path

Q: Starting from home, Amit walks 40 m North, then 30 m East, then 40 m South, then 20 m West. How far is he from home?

Solution:

Step 1: Draw and track

           B (30m E)
           |
           |
Home ------A (40m N)
|          |
|          C (40m S)
|__________|
    D (20m W)

Net North-South:
40 m North - 40 m South = 0 m

Net East-West:
30 m East - 20 m West = 10 m East

Step 2: Final position

Amit is 10 m East of home
Distance = 10 m

Answer: 10 m


Example 6: Shadow Problem

Q: One morning, Rajiv was facing a pole. The shadow of the pole fell exactly to his right. Which direction was he facing?

Solution:

Step 1: Understand shadow direction

Morning: Sun is in the EAST
Shadow falls opposite to sun = WEST direction

Step 2: Determine facing

Shadow fell to his RIGHT = Shadow in WEST
If West is to the right, then:
He must be facing NORTH

Verification:
Facing North β†’ Right = East? NO
Facing North β†’ Right = West? NO

Wait! Let's reconsider:
Facing direction + Right side = West

If facing North: Right = East βœ—
If facing South: Right = West βœ“

Answer: South


⚑ Quick Formulas & Shortcuts

Formula 1: Pythagoras Theorem

For right-angled triangle:
Shortest distance = √(a² + b²)

Common Pythagorean triplets (memorize!):
3-4-5 (3Β² + 4Β² = 5Β²)
5-12-13
8-15-17
7-24-25

Formula 2: Net Displacement

Net North-South = (Total North) - (Total South)
Net East-West = (Total East) - (Total West)

Final distance = √[(Net N-S)² + (Net E-W)²]

Formula 3: Turn Counting

Total right turns (R), Total left turns (L)

Net turns = |R - L|

If R > L: Net right turns = R - L
If L > R: Net left turns = L - R

Formula 4: Shadow Direction

Morning (before noon): Sun in EAST, Shadow in WEST
Evening (after noon): Sun in WEST, Shadow in EAST

If shadow to your LEFT:
- Morning: Facing SOUTH
- Evening: Facing NORTH

If shadow to your RIGHT:
- Morning: Facing NORTH
- Evening: Facing SOUTH

πŸ“Š Direction Table

Right Turn Sequence (Clockwise)

Current Direction After 1 Right After 2 Right After 3 Right After 4 Right
North East South West North
East South West North East
South West North East South
West North East South West

Left Turn Sequence (Anti-clockwise)

Current Direction After 1 Left After 2 Left After 3 Left After 4 Left
North West South East North
East North West South East
South East North West South
West South East North West

⚠️ Common Mistakes

❌ Mistake 1: Left-Right Confusion

Wrong: Right turn from North = West βœ—
Right: Right turn from North = East βœ“

Remember: RIGHT = CLOCKWISE (N β†’ E β†’ S β†’ W)

❌ Mistake 2: Shadow Direction

Wrong: Morning shadow always falls East βœ—
Right: Morning shadow falls WEST (opposite to sun) βœ“

❌ Mistake 3: Forgetting to Square Root

Wrong: Distance = 3Β² + 4Β² = 25 km βœ—
Right: Distance = √(3Β² + 4Β²) = √25 = 5 km βœ“

❌ Mistake 4: Not Simplifying First

Wrong: Calculate √(40Β² + 30Β²) directly βœ—
Right: Simplify to √(4Β² Γ— 10Β² + 3Β² Γ— 10Β²) = 10√(16+9) = 50 km βœ“

❌ Mistake 5: Diagonal as Straight

Wrong: 10 km NE = 10 km North + 10 km East βœ—
Right: 10 km NE = 7.07 km North + 7.07 km East βœ“

🎯 Advanced Patterns

Pattern 1: Minimum Distance Between Two Movers

Q: A and B start from the same point. A goes 5 km North, B goes 5 km East. What is distance between them?

Solution:

    A
    |
    | 5 km
    |
Start ---- 5 km ---- B

Distance AB = √(5² + 5²) = √50 = 5√2 km

Pattern 2: Meeting Point Problems

Q: A walks 3 km North. B walks 4 km East from the same starting point. If they walk towards each other in straight line, where do they meet?

Solution:

They meet at a point on the straight line connecting them.
The straight line distance = √(3² + 4²) = 5 km

Pattern 3: Circular Path

Q: A person walks in a square path: 10m North, 10m East, 10m South, 10m West. What is displacement?

Solution:

     10m E
  +------+
  |      |
10m N    | 10m S
  |      |
  +------+
    10m W

Net displacement = 0 (back to starting point)

πŸ“ Practice Problems

Level 1: Basic Direction

1. A man walks 8 km South, then 6 km East. What is the shortest distance from start?

2. Facing North, a person turns right, then right again. Which direction is he facing?

3. The shadow of a pole falls to the North in the evening. Where is the sun?


Level 2: Medium

4. Ram walks 10 km North, 6 km East, 10 km South, 6 km West. How far from starting point?

5. A person walks 7 km East, then turns 135Β° clockwise and walks 7 km. Find final direction.

6. A faces North. After 3 right turns and 2 left turns, which direction does he face?


Level 3: Hard

7. A walks 15 km North, then turns right and walks 20 km, then turns right and walks 15 km. Final distance from start?

8. One morning, Suresh was facing a tree. The shadow of the tree fell exactly behind him. Which direction was he facing?

9. A walks 12 km North-West. What is his displacement in North and West directions separately?


🎯 Special Cases

Case 1: 3-4-5 Triangle (Most Common)

If distances are multiples of 3 and 4:
Answer is multiple of 5

Example:
6 km North + 8 km East = 10 km (2 Γ— 5)
9 km North + 12 km East = 15 km (3 Γ— 5)

Case 2: Equal Perpendicular Distances

If both distances are equal:
Answer = Distance Γ— √2

Example:
5 km North + 5 km East = 5√2 km β‰ˆ 7.07 km
10 km North + 10 km West = 10√2 km β‰ˆ 14.14 km

Case 3: Opposite Direction Cancellation

If movement in opposite directions:
They cancel out

Example:
10 km North + 7 km South = Net 3 km North
15 km East + 15 km West = Net 0 km

🎯 Exam Strategy

Time Management:

  • Per question: 45-60 seconds
  • For 5 direction questions: 4-5 minutes

Quick Approach:

  1. Draw rough diagram (15 sec) - Always!
  2. Track movements (15 sec)
  3. Calculate net displacement (15 sec)
  4. Apply Pythagoras (10 sec)
  5. Verify (5 sec)

Priority:

  • βœ… Simple turn questions - 25 sec
  • βœ… Distance with 3-4-5 triplets - 35 sec
  • βœ… Shadow problems - 30 sec
  • ⏭️ Complex multi-step paths - 60+ sec

Uses Concepts From:

  • Basic geometry (Pythagoras theorem)
  • Angle measurement
  • Coordinate geometry

Related Reasoning Topics:

Practice:


Master Direction Sense - Draw diagrams, use Pythagoras! 🧭