Data Sufficiency Question 48
Directions : Each of the questions given below consists of a question and two statements numbered I and II given below it. You have to decide whether the data provided in the statements sufficient to answer the question. Read both the statements and
(IBPS Specialist Officer (IT) CWE 14.02.2016)
Give answer (1) if the data in statement I alone are sufficient to answer the question, while the data in statement II alone are not sufficient to answer the question.
Give answer (2) if the data in statement II alone are sufficient to answer the question, while the data in statement I alone are not sufficient to answer the question.
- There are five floors in a building named from number 1 to 5 in such a way that lowermost floor is numbered as 1 and topmost floor is numbered as 5. Five members live at different floors of the building namely, Rama, Lina, Tina, Charu and Anita, but not necessarily in the same order, Also these five work in different companies namely, A, B, $C, D$ and $E$. Tina stays on floor no. 2 and works in company D and Charu stays on floor no. 5. Also the one who stays on floor no. 1 is working in company $A$. Then who lives on floor no. 3 and in which company does she/he work?
I. Neither Lina nor Anita works in company A.
II. One who lives on floor 3 works in company $C$.
III. Anita does not work in company C.
(1) Statement I and statement II together are sufficient.
(2) Any two statements together are not necessarily sufficient.
(3) Either statement I and statement II together, or statement II and III together, are sufficient.
(4) All the statements I, II and III together are sufficient.
(5) None are sufficient. (SBI PO Phase-II (Main) Exam 05.08.2018)
Show Answer
Correct Answer: 48. (3)
Solution: 48. (3) From statement III,
$(A+B+C)$ ’s 1 day’s work
$=\frac{13}{48}$
$(A+2B+C)$’s 1 day’s work
$=\frac{5}{24}+\frac{7}{48}=\frac{10+7}{48}=\frac{17}{48}$
$\therefore$ B’s 1 day’s work
$=\frac{17}{48}-\frac{13}{48}=\frac{4}{48}=\frac{1}{12}$
$\therefore$ Required time $=12$ days
From statement II,
$(A + B + C)$’s 1 day’s work
$=\frac{13}{48}$
$(A+C)$ ’s 1 day’s work $=\frac{3}{16}$
$\therefore$ B’s 1 day’s work
$=\frac{13}{48}-\frac{3}{16}$
$=\frac{13-9}{48}=\frac{4}{48}=\frac{1}{12}$
Required time $=12$ days
BETA
