Data Sufficiency Question 39
Directions : Each of the questions given below consists of a question and two statements numbered I and II given below it. You have to decide whether the data provided in the statements sufficient to answer the question. Read both the statements and
(SIDBI Bank Officer Exam. 09.09.2014)
Give answer (1) if the data in statement I alone are sufficient to answer the question, while the data in statement II alone are not sufficient to answer the question.
Give answer (2) if the data in statement II alone are sufficient to answer the question, while the data in statement I alone are not sufficient to answer the question.
Give answer (3) if the data in statement I alone or in statement II alone are sufficient to answer the question.
Give answer (4) if the data in both the statements I and II are not sufficient to answer the question.
Give answer (5) if the data in both the statements I and II together are necessary to answer the question.
- There are three inlets A, B and C and an outlet D in a tank. If all the four pipes are opened simultaneously in what time will the tank be filled?
I. The ratio of time taken by pipes $A, B$ and $C$ separately in filling the tank is $2: 3: 4$ respectively.
II. Outlet D can empty the full tank in 2 hours that is thrice the time taken by pipes $A$ and C together in filling the tank.
Show Answer
Correct Answer: 39. (5)
Solution: 39. (5) From statement I,
Pipe $A \Rightarrow 2 x$ hours
Pipe $\mathrm{B} \Rightarrow 3 x$ hours
Pipe $\mathrm{C} \Rightarrow 4 x$ hours
From statements II,
Part of the tank filled by pipes A and $\mathrm{C}$ in 1 hour
$=\frac{1}{2 x}+\frac{1}{4 x}$
$=\frac{2+1}{4 x}=\frac{3}{4 x}$
i.e., time taken in filling the tank
$=\frac{4 x}{3}$ hours
$\therefore \frac{3 \times 4 x}{3}=2$
$\Rightarrow x=\frac{1}{2}$
On opening the four pipes simultaneously,
Part of the tank filled in 1 hour
$=\frac{1}{2 x}+\frac{1}{3 x}+\frac{1}{4 x}-\frac{1}{2}$
$=\frac{6+4+3}{12 x}-\frac{1}{2}$
$=\frac{13}{12 x}-\frac{1}{2}$
$=\frac{13}{6}-\frac{1}{2}$
$=\frac{13-3}{6}=\frac{10}{6}=\frac{5}{3}$
$\therefore$ Required time $=\frac{3}{5}$ hour.
BETA
